Package g0801_0900.s0844_backspace_string_compare

Class Solution

java.lang.Object
g0801_0900.s0844_backspace_string_compare.Solution
public class Solution extends java.lang.Object
844 - Backspace String Compare.

Easy

Given two strings s and t, return true if they are equal when both are typed into empty text editors. '#' means a backspace character.

Note that after backspacing an empty text, the text will continue empty.

Example 1:

Input: s = “ab#c”, t = “ad#c”

Output: true

Explanation: Both s and t become “ac”.

Example 2:

Input: s = “ab##”, t = “c#d#”

Output: true

Explanation: Both s and t become "".

Example 3:

Input: s = “a#c”, t = “b”

Output: false

Explanation: s becomes “c” while t becomes “b”.

Constraints:

  • 1 <= s.length, t.length <= 200
  • s and t only contain lowercase letters and '#' characters.

Follow up: Can you solve it in O(n) time and O(1) space?

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    boolean
    backspaceCompare(java.lang.String s, java.lang.String t)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • backspaceCompare

      public boolean backspaceCompare(java.lang.String s, java.lang.String t)