java.lang.Object
g0801_0900.s0898_bitwise_ors_of_subarrays.Solution

public class Solution extends java.lang.Object
898 - Bitwise ORs of Subarrays.

Medium

We have an array arr of non-negative integers.

For every (contiguous) subarray sub = [arr[i], arr[i + 1], ..., arr[j]] (with i <= j), we take the bitwise OR of all the elements in sub, obtaining a result arr[i] | arr[i + 1] | ... | arr[j].

Return the number of possible results. Results that occur more than once are only counted once in the final answer

Example 1:

Input: arr = [0]

Output: 1

Explanation: There is only one possible result: 0.

Example 2:

Input: arr = [1,1,2]

Output: 3

Explanation:

 The possible subarrays are [1], [1], [2], [1, 1], [1, 2], [1, 1, 2].
 These yield the results 1, 1, 2, 1, 3, 3.
 There are 3 unique values, so the answer is 3. 

Example 3:

Input: arr = [1,2,4]

Output: 6

Explanation: The possible results are 1, 2, 3, 4, 6, and 7.

Constraints:

  • 1 <= nums.length <= 5 * 104
  • 0 <= nums[i] <= 109
  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    int
    subarrayBitwiseORs(int[] arr)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • subarrayBitwiseORs

      public int subarrayBitwiseORs(int[] arr)