java.lang.Object
g0901_1000.s0922_sort_array_by_parity_ii.Solution

public class Solution extends java.lang.Object
922 - Sort Array By Parity II.

Easy

Given an array of integers nums, half of the integers in nums are odd , and the other half are even.

Sort the array so that whenever nums[i] is odd, i is odd , and whenever nums[i] is even, i is even.

Return any answer array that satisfies this condition.

Example 1:

Input: nums = [4,2,5,7]

Output: [4,5,2,7]

Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.

Example 2:

Input: nums = [2,3]

Output: [2,3]

Constraints:

  • 2 <= nums.length <= 2 * 104
  • nums.length is even.
  • Half of the integers in nums are even.
  • 0 <= nums[i] <= 1000

Follow Up: Could you solve it in-place?

  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    int[]
    sortArrayByParityII(int[] nums)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • sortArrayByParityII

      public int[] sortArrayByParityII(int[] nums)