java.lang.Object
g1001_1100.s1043_partition_array_for_maximum_sum.Solution

public class Solution extends java.lang.Object
1043 - Partition Array for Maximum Sum.

Medium

Given an integer array arr, partition the array into (contiguous) subarrays of length at most k. After partitioning, each subarray has their values changed to become the maximum value of that subarray.

Return the largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a 32-bit integer.

Example 1:

Input: arr = [1,15,7,9,2,5,10], k = 3

Output: 84

Explanation: arr becomes [15,15,15,9,10,10,10]

Example 2:

Input: arr = [1,4,1,5,7,3,6,1,9,9,3], k = 4

Output: 83

Example 3:

Input: arr = [1], k = 1

Output: 1

Constraints:

  • 1 <= arr.length <= 500
  • 0 <= arr[i] <= 109
  • 1 <= k <= arr.length
  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    int
    maxSumAfterPartitioning(int[] arr, int k)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • maxSumAfterPartitioning

      public int maxSumAfterPartitioning(int[] arr, int k)