Package g1101_1200.s1170_compare_strings_by_frequency_of_the_smallest_character

Class Solution

java.lang.Object
g1101_1200.s1170_compare_strings_by_frequency_of_the_smallest_character.Solution
public class Solution extends java.lang.Object
1170 - Compare Strings by Frequency of the Smallest Character.

Medium

Let the function f(s) be the frequency of the lexicographically smallest character in a non-empty string s. For example, if s = "dcce" then f(s) = 2 because the lexicographically smallest character is 'c', which has a frequency of 2.

You are given an array of strings words and another array of query strings queries. For each query queries[i], count the number of words in words such that f(queries[i]) < f(W) for each W in words.

Return an integer array answer, where each answer[i] is the answer to the ith query.

Example 1:

Input: queries = [“cbd”], words = [“zaaaz”]

Output: [1]

Explanation: On the first query we have f(“cbd”) = 1, f(“zaaaz”) = 3 so f(“cbd”) < f(“zaaaz”).

Example 2:

Input: queries = [“bbb”,“cc”], words = [“a”,“aa”,“aaa”,“aaaa”]

Output: [1,2]

Explanation: On the first query only f(“bbb”) < f(“aaaa”). On the second query both f(“aaa”) and f(“aaaa”) are both > f(“cc”).

Constraints:

  • 1 <= queries.length <= 2000
  • 1 <= words.length <= 2000
  • 1 <= queries[i].length, words[i].length <= 10
  • queries[i][j], words[i][j] consist of lowercase English letters.

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    int[]
    numSmallerByFrequency(java.lang.String[] queries, java.lang.String[] words)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • numSmallerByFrequency

      public int[] numSmallerByFrequency(java.lang.String[] queries, java.lang.String[] words)