Package g1401_1500.s1433_check_if_a_string_can_break_another_string

Class Solution

java.lang.Object
g1401_1500.s1433_check_if_a_string_can_break_another_string.Solution
public class Solution extends java.lang.Object
1433 - Check If a String Can Break Another String.

Medium

Given two strings: s1 and s2 with the same size, check if some permutation of string s1 can break some permutation of string s2 or vice-versa. In other words s2 can break s1 or vice-versa.

A string x can break string y (both of size n) if x[i] >= y[i] (in alphabetical order) for all i between 0 and n-1.

Example 1:

Input: s1 = “abc”, s2 = “xya”

Output: true

Explanation: “ayx” is a permutation of s2=“xya” which can break to string “abc” which is a permutation of s1=“abc”.

Example 2:

Input: s1 = “abe”, s2 = “acd”

Output: false

Explanation: All permutations for s1=“abe” are: “abe”, “aeb”, “bae”, “bea”, “eab” and “eba” and all permutation for s2=“acd” are: “acd”, “adc”, “cad”, “cda”, “dac” and “dca”. However, there is not any permutation from s1 which can break some permutation from s2 and vice-versa.

Example 3:

Input: s1 = “leetcodee”, s2 = “interview”

Output: true

Constraints:

  • s1.length == n
  • s2.length == n
  • 1 <= n <= 10^5
  • All strings consist of lowercase English letters.

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    boolean
    checkIfCanBreak(java.lang.String s1, java.lang.String s2)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • checkIfCanBreak

      public boolean checkIfCanBreak(java.lang.String s1, java.lang.String s2)