Class Solution

java.lang.Object
g1501_1600.s1529_bulb_switcher_iv.Solution

public class Solution extends java.lang.Object
1529 - Minimum Suffix Flips.

Medium

You are given a 0-indexed binary string target of length n. You have another binary string s of length n that is initially set to all zeros. You want to make s equal to target.

In one operation, you can pick an index i where 0 <= i < n and flip all bits in the inclusive range [i, n - 1]. Flip means changing '0' to '1' and '1' to '0'.

Return the minimum number of operations needed to make s equal to target.

Example 1:

Input: target = “10111”

Output: 3

Explanation: Initially, s = “00000”.

Choose index i = 2: “00000” -> “00111”

Choose index i = 0: “00111” -> “11000”

Choose index i = 1: “11000” -> “10111”

We need at least 3 flip operations to form target.

Example 2:

Input: target = “101”

Output: 3

Explanation: Initially, s = “000”.

Choose index i = 0: “000” -> “111”

Choose index i = 1: “111” -> “100”

Choose index i = 2: “100” -> “101”

We need at least 3 flip operations to form target.

Example 3:

Input: target = “00000”

Output: 0

Explanation: We do not need any operations since the initial s already equals target.

Constraints:

  • n == target.length
  • 1 <= n <= 105
  • target[i] is either '0' or '1'.
  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    int
    minFlips(java.lang.String target)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • minFlips

      public int minFlips(java.lang.String target)