Class Solution
Easy
Given an integer n
and an integer array rounds
. We have a circular track which consists of n
sectors labeled from 1
to n
. A marathon will be held on this track, the marathon consists of m
rounds. The ith
round starts at sector rounds[i - 1]
and ends at sector rounds[i]
. For example, round 1 starts at sector rounds[0]
and ends at sector rounds[1]
Return an array of the most visited sectors sorted in ascending order.
Notice that you circulate the track in ascending order of sector numbers in the counter-clockwise direction (See the first example).
Example 1:
Input: n = 4, rounds = [1,3,1,2]
Output: [1,2]
Explanation: The marathon starts at sector 1. The order of the visited sectors is as follows: 1 –> 2 –> 3 (end of round 1) –> 4 –> 1 (end of round 2) –> 2 (end of round 3 and the marathon) We can see that both sectors 1 and 2 are visited twice and they are the most visited sectors. Sectors 3 and 4 are visited only once.
Example 2:
Input: n = 2, rounds = [2,1,2,1,2,1,2,1,2]
Output: [2]
Example 3:
Input: n = 7, rounds = [1,3,5,7]
Output: [1,2,3,4,5,6,7]
Constraints:
2 <= n <= 100
1 <= m <= 100
rounds.length == m + 1
1 <= rounds[i] <= n
rounds[i] != rounds[i + 1]
for0 <= i < m
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Constructor Summary
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Method Summary
Modifier and TypeMethodDescriptionjava.util.List
<java.lang.Integer> mostVisited
(int n, int[] rounds) Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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mostVisited
public java.util.List<java.lang.Integer> mostVisited(int n, int[] rounds)
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