java.lang.Object
g1501_1600.s1592_rearrange_spaces_between_words.Solution

public class Solution extends java.lang.Object
1592 - Rearrange Spaces Between Words.

Easy

You are given a string text of words that are placed among some number of spaces. Each word consists of one or more lowercase English letters and are separated by at least one space. It’s guaranteed that text contains at least one word.

Rearrange the spaces so that there is an equal number of spaces between every pair of adjacent words and that number is maximized. If you cannot redistribute all the spaces equally, place the extra spaces at the end , meaning the returned string should be the same length as text.

Return the string after rearranging the spaces.

Example 1:

Input: text = " this is a sentence "

Output: “this is a sentence”

Explanation: There are a total of 9 spaces and 4 words. We can evenly divide the 9 spaces between the words: 9 / (4-1) = 3 spaces.

Example 2:

Input: text = " practice makes perfect"

Output: "practice makes perfect "

Explanation: There are a total of 7 spaces and 3 words. 7 / (3-1) = 3 spaces plus 1 extra space. We place this extra space at the end of the string.

Constraints:

  • 1 <= text.length <= 100
  • text consists of lowercase English letters and ' '.
  • text contains at least one word.
  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    java.lang.String
    reorderSpaces(java.lang.String text)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • reorderSpaces

      public java.lang.String reorderSpaces(java.lang.String text)