Class Solution
Easy
There is a malfunctioning keyboard where some letter keys do not work. All other keys on the keyboard work properly.
Given a string text
of words separated by a single space (no leading or trailing spaces) and a string brokenLetters
of all distinct letter keys that are broken, return the number of words in text
you can fully type using this keyboard.
Example 1:
Input: text = “hello world”, brokenLetters = “ad”
Output: 1
Explanation: We cannot type “world” because the ‘d’ key is broken.
Example 2:
Input: text = “leet code”, brokenLetters = “lt”
Output: 1
Explanation: We cannot type “leet” because the ‘l’ and ‘t’ keys are broken.
Example 3:
Input: text = “leet code”, brokenLetters = “e”
Output: 0
Explanation: We cannot type either word because the ‘e’ key is broken.
Constraints:
1 <= text.length <= 104
0 <= brokenLetters.length <= 26
text
consists of words separated by a single space without any leading or trailing spaces.- Each word only consists of lowercase English letters.
brokenLetters
consists of distinct lowercase English letters.
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Constructor Summary
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Method Summary
Modifier and TypeMethodDescriptionint
canBeTypedWords
(java.lang.String text, java.lang.String brokenLetters) Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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canBeTypedWords
public int canBeTypedWords(java.lang.String text, java.lang.String brokenLetters)
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