Class Solution
Medium
You are given a 0-indexed integer array piles
, where piles[i]
represents the number of stones in the ith
pile, and an integer k
. You should apply the following operation exactly k
times:
- Choose any
piles[i]
and removefloor(piles[i] / 2)
stones from it.
Notice that you can apply the operation on the same pile more than once.
Return the minimum possible total number of stones remaining after applying the k
operations.
floor(x)
is the greatest integer that is smaller than or equal to x
(i.e., rounds x
down).
Example 1:
Input: piles = [5,4,9], k = 2
Output: 12
Explanation: Steps of a possible scenario are:
-
Apply the operation on pile 2. The resulting piles are [5,4,5].
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Apply the operation on pile 0. The resulting piles are [3,4,5].
The total number of stones in [3,4,5] is 12.
Example 2:
Input: piles = [4,3,6,7], k = 3
Output: 12
Explanation: Steps of a possible scenario are:
-
Apply the operation on pile 2. The resulting piles are [4,3,3,7].
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Apply the operation on pile 3. The resulting piles are [4,3,3,4].
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Apply the operation on pile 0. The resulting piles are [2,3,3,4].
The total number of stones in [2,3,3,4] is 12.
Constraints:
1 <= piles.length <= 105
1 <= piles[i] <= 104
1 <= k <= 105
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Constructor Summary
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Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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minStoneSum
public int minStoneSum(int[] piles, int k)
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