Class Solution

java.lang.Object
g2101_2200.s2104_sum_of_subarray_ranges.Solution

public class Solution extends java.lang.Object
2104 - Sum of Subarray Ranges.

Medium

You are given an integer array nums. The range of a subarray of nums is the difference between the largest and smallest element in the subarray.

Return the sum of all subarray ranges of nums.

A subarray is a contiguous non-empty sequence of elements within an array.

Example 1:

Input: nums = [1,2,3]

Output: 4

Explanation: The 6 subarrays of nums are the following:

[1], range = largest - smallest = 1 - 1 = 0

[2], range = 2 - 2 = 0

[3], range = 3 - 3 = 0

[1,2], range = 2 - 1 = 1

[2,3], range = 3 - 2 = 1

[1,2,3], range = 3 - 1 = 2

So the sum of all ranges is 0 + 0 + 0 + 1 + 1 + 2 = 4.

Example 2:

Input: nums = [1,3,3]

Output: 4

Explanation: The 6 subarrays of nums are the following:

[1], range = largest - smallest = 1 - 1 = 0

[3], range = 3 - 3 = 0

[3], range = 3 - 3 = 0

[1,3], range = 3 - 1 = 2

[3,3], range = 3 - 3 = 0

[1,3,3], range = 3 - 1 = 2

So the sum of all ranges is 0 + 0 + 0 + 2 + 0 + 2 = 4.

Example 3:

Input: nums = [4,-2,-3,4,1]

Output: 59

Explanation: The sum of all subarray ranges of nums is 59.

Constraints:

  • 1 <= nums.length <= 1000
  • -109 <= nums[i] <= 109

Follow-up: Could you find a solution with O(n) time complexity?

  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    long
    subArrayRanges(int[] nums)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • subArrayRanges

      public long subArrayRanges(int[] nums)