Class Solution
Hard
You are building a string s of length n one character at a time, prepending each new character to the front of the string. The strings are labeled from 1 to n, where the string with length i is labeled si.
- For example, for
s = "abaca",s1 == “a”,s2 == “ca”,s3 == “aca”, etc.
The score of si is the length of the longest common prefix between si and sn (Note that s == sn).
Given the final string s, return the sum of the score of every si.
Example 1:
Input: s = “babab”
Output: 9
Explanation: For s1 == “b”, the longest common prefix is “b” which has a score of 1.
For s2 == “ab”, there is no common prefix so the score is 0.
For s3 == “bab”, the longest common prefix is “bab” which has a score of 3.
For s4 == “abab”, there is no common prefix so the score is 0.
For s5 == “babab”, the longest common prefix is “babab” which has a score of 5.
The sum of the scores is 1 + 0 + 3 + 0 + 5 = 9, so we return 9.
Example 2:
Input: s = “azbazbzaz”
Output: 14
Explanation:
For s2 == “az”, the longest common prefix is “az” which has a score of 2.
For s6 == “azbzaz”, the longest common prefix is “azb” which has a score of 3.
For s9 == “azbazbzaz”, the longest common prefix is “azbazbzaz” which has a score of 9.
For all other si, the score is 0.
The sum of the scores is 2 + 3 + 9 = 14, so we return 14.
Constraints:
1 <= s.length <= 105sconsists of lowercase English letters.
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Constructor Summary
Constructors -
Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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sumScores
public long sumScores(java.lang.String s)
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