Class Solution
Hard
You are given a 0-indexed 2D integer array grid
of size m x n
. Each cell has one of two values:
0
represents an empty cell,1
represents an obstacle that may be removed.
You can move up, down, left, or right from and to an empty cell.
Return the minimum number of obstacles to remove so you can move from the upper left corner (0, 0)
to the lower right corner (m - 1, n - 1)
.
Example 1:
Input: grid = [[0,1,1],[1,1,0],[1,1,0]]
Output: 2
Explanation: We can remove the obstacles at (0, 1) and (0, 2) to create a path from (0, 0) to (2, 2).
It can be shown that we need to remove at least 2 obstacles, so we return 2.
Note that there may be other ways to remove 2 obstacles to create a path.
Example 2:
Input: grid = [[0,1,0,0,0],[0,1,0,1,0],[0,0,0,1,0]]
Output: 0
Explanation: We can move from (0, 0) to (2, 4) without removing any obstacles, so we return 0.
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 105
2 <= m * n <= 105
grid[i][j]
is either0
or1
.grid[0][0] == grid[m - 1][n - 1] == 0
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Constructor Summary
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Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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minimumObstacles
public int minimumObstacles(int[][] grid)
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