Package g2401_2500.s2446_determine_if_two_events_have_conflict

Class Solution

java.lang.Object
g2401_2500.s2446_determine_if_two_events_have_conflict.Solution
public class Solution extends java.lang.Object
2446 - Determine if Two Events Have Conflict.

Easy

You are given two arrays of strings that represent two inclusive events that happened on the same day , event1 and event2, where:

  • event1 = [startTime1, endTime1] and
  • event2 = [startTime2, endTime2].

Event times are valid 24 hours format in the form of HH:MM.

A conflict happens when two events have some non-empty intersection (i.e., some moment is common to both events).

Return true if there is a conflict between two events. Otherwise, return false.

Example 1:

Input: event1 = [“01:15”,“02:00”], event2 = [“02:00”,“03:00”]

Output: true

Explanation: The two events intersect at time 2:00.

Example 2:

Input: event1 = [“01:00”,“02:00”], event2 = [“01:20”,“03:00”]

Output: true

Explanation: The two events intersect starting from 01:20 to 02:00.

Example 3:

Input: event1 = [“10:00”,“11:00”], event2 = [“14:00”,“15:00”]

Output: false

Explanation: The two events do not intersect.

Constraints:

  • evnet1.length == event2.length == 2.
  • event1[i].length == event2[i].length == 5
  • startTime1 <= endTime1
  • startTime2 <= endTime2
  • All the event times follow the HH:MM format.

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    boolean
    haveConflict(java.lang.String[] event1, java.lang.String[] event2)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • haveConflict

      public boolean haveConflict(java.lang.String[] event1, java.lang.String[] event2)