Class Solution
java.lang.Object
g2501_2600.s2552_count_increasing_quadruplets.Solution
public class Solution
extends java.lang.Object
2552 - Count Increasing Quadruplets.
Hard
Given a 0-indexed integer array nums
of size n
containing all numbers from 1
to n
, return the number of increasing quadruplets.
A quadruplet (i, j, k, l)
is increasing if:
0 <= i < j < k < l < n
, andnums[i] < nums[k] < nums[j] < nums[l]
.
Example 1:
Input: nums = [1,3,2,4,5]
Output: 2
Explanation:
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When i = 0, j = 1, k = 2, and l = 3, nums[i] < nums[k] < nums[j] < nums[l].
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When i = 0, j = 1, k = 2, and l = 4, nums[i] < nums[k] < nums[j] < nums[l]. There are no other quadruplets, so we return 2.
Example 2:
Input: nums = [1,2,3,4]
Output: 0
Explanation:
There exists only one quadruplet with i = 0, j = 1, k = 2, l = 3, but since nums[j] < nums[k], we return 0.
Constraints:
4 <= nums.length <= 4000
1 <= nums[i] <= nums.length
- All the integers of
nums
are unique.nums
is a permutation.
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Constructor Summary
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Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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countQuadruplets
public long countQuadruplets(int[] nums)
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