Class Solution

java.lang.Object
g2601_2700.s2643_row_with_maximum_ones.Solution

public class Solution extends java.lang.Object
2643 - Row With Maximum Ones.

Easy

Given a m x n binary matrix mat, find the 0-indexed position of the row that contains the maximum count of **ones, ** and the number of ones in that row.

In case there are multiple rows that have the maximum count of ones, the row with the smallest row number should be selected.

Return an array containing the index of the row, and the number of ones in it.

Example 1:

Input: mat = [[0,1],[1,0]]

Output: [0,1]

Explanation: Both rows have the same number of 1’s. So we return the index of the smaller row, 0, and the maximum count of ones (1). So, the answer is [0,1].

Example 2:

Input: mat = [[0,0,0],[0,1,1]]

Output: [1,2]

Explanation: The row indexed 1 has the maximum count of ones (2). So we return its index, 1, and the count. So, the answer is [1,2].

Example 3:

Input: mat = [[0,0],[1,1],[0,0]]

Output: [1,2]

Explanation: The row indexed 1 has the maximum count of ones (2). So the answer is [1,2].

Constraints:

  • m == mat.length
  • n == mat[i].length
  • 1 <= m, n <= 100
  • mat[i][j] is either 0 or 1.
  • Constructor Summary

    Constructors
    Constructor
    Description
     
  • Method Summary

    Modifier and Type
    Method
    Description
    int[]
    rowAndMaximumOnes(int[][] mat)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • rowAndMaximumOnes

      public int[] rowAndMaximumOnes(int[][] mat)