Package g2701_2800.s2790_maximum_number_of_groups_with_increasing_length

Class Solution

java.lang.Object
g2701_2800.s2790_maximum_number_of_groups_with_increasing_length.Solution
public class Solution extends java.lang.Object
2790 - Maximum Number of Groups With Increasing Length.

Hard

You are given a 0-indexed array usageLimits of length n.

Your task is to create groups using numbers from 0 to n - 1, ensuring that each number, i, is used no more than usageLimits[i] times in total across all groups. You must also satisfy the following conditions:

  • Each group must consist of distinct numbers, meaning that no duplicate numbers are allowed within a single group.
  • Each group (except the first one) must have a length strictly greater than the previous group.

Return an integer denoting the maximum number of groups you can create while satisfying these conditions.

Example 1:

Input: usageLimits = [1,2,5]

Output: 3

Explanation:

In this example, we can use 0 at most once, 1 at most twice, and 2 at most five times.

One way of creating the maximum number of groups while satisfying the conditions is:

Group 1 contains the number [2].

Group 2 contains the numbers [1,2].

Group 3 contains the numbers [0,1,2].

It can be shown that the maximum number of groups is 3.

So, the output is 3.

Example 2:

Input: usageLimits = [2,1,2]

Output: 2

Explanation:

In this example, we can use 0 at most twice, 1 at most once, and 2 at most twice.

One way of creating the maximum number of groups while satisfying the conditions is:

Group 1 contains the number [0].

Group 2 contains the numbers [1,2].

It can be shown that the maximum number of groups is 2.

So, the output is 2.

Example 3:

Input: usageLimits = [1,1]

Output: 1

Explanation:

In this example, we can use both 0 and 1 at most once.

One way of creating the maximum number of groups while satisfying the conditions is:

Group 1 contains the number [0].

It can be shown that the maximum number of groups is 1.

So, the output is 1.

Constraints:

  • 1 <= usageLimits.length <= 105
  • 1 <= usageLimits[i] <= 109

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    int
    maxIncreasingGroups(java.util.List<java.lang.Integer> usageLimits)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • maxIncreasingGroups

      public int maxIncreasingGroups(java.util.List<java.lang.Integer> usageLimits)