Package g2901_3000.s3000_maximum_area_of_longest_diagonal_rectangle

Class Solution

java.lang.Object
g2901_3000.s3000_maximum_area_of_longest_diagonal_rectangle.Solution
public class Solution extends java.lang.Object
3000 - Maximum Area of Longest Diagonal Rectangle.

Easy

You are given a 2D 0-indexed integer array dimensions.

For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle i.

Return the area of the rectangle having the longest diagonal. If there are multiple rectangles with the longest diagonal, return the area of the rectangle having the maximum area.

Example 1:

Input: dimensions = [[9,3],[8,6]]

Output: 48

Explanation:

For index = 0, length = 9 and width = 3. Diagonal length = sqrt(9 * 9 + 3 * 3) = sqrt(90) \u2248 9.487.

For index = 1, length = 8 and width = 6. Diagonal length = sqrt(8 * 8 + 6 * 6) = sqrt(100) = 10.

So, the rectangle at index 1 has a greater diagonal length therefore we return area = 8 * 6 = 48.

Example 2:

Input: dimensions = [[3,4],[4,3]]

Output: 12

Explanation: Length of diagonal is the same for both which is 5, so maximum area = 12.

Constraints:

  • 1 <= dimensions.length <= 100
  • dimensions[i].length == 2
  • 1 <= dimensions[i][0], dimensions[i][1] <= 100

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    int
    areaOfMaxDiagonal(int[][] dimensions)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • areaOfMaxDiagonal

      public int areaOfMaxDiagonal(int[][] dimensions)