Package g3001_3100.s3048_earliest_second_to_mark_indices_i

Class Solution

java.lang.Object
g3001_3100.s3048_earliest_second_to_mark_indices_i.Solution
public class Solution extends java.lang.Object
3048 - Earliest Second to Mark Indices I.

Medium

You are given two 1-indexed integer arrays, nums and, changeIndices, having lengths n and m, respectively.

Initially, all indices in nums are unmarked. Your task is to mark all indices in nums.

In each second, s, in order from 1 to m ( inclusive ), you can perform one of the following operations:

  • Choose an index i in the range [1, n] and decrement nums[i] by 1.
  • If nums[changeIndices[s]] is equal to 0, mark the index changeIndices[s].
  • Do nothing.

Return an integer denoting the earliest second in the range [1, m] when all indices in nums can be marked by choosing operations optimally, or -1 if it is impossible.

Example 1:

Input: nums = [2,2,0], changeIndices = [2,2,2,2,3,2,2,1]

Output: 8

Explanation: In this example, we have 8 seconds. The following operations can be performed to mark all indices:

Second 1: Choose index 1 and decrement nums[1] by one. nums becomes [1,2,0].

Second 2: Choose index 1 and decrement nums[1] by one. nums becomes [0,2,0].

Second 3: Choose index 2 and decrement nums[2] by one. nums becomes [0,1,0].

Second 4: Choose index 2 and decrement nums[2] by one. nums becomes [0,0,0].

Second 5: Mark the index changeIndices[5], which is marking index 3, since nums[3] is equal to 0.

Second 6: Mark the index changeIndices[6], which is marking index 2, since nums[2] is equal to 0.

Second 7: Do nothing.

Second 8: Mark the index changeIndices[8], which is marking index 1, since nums[1] is equal to 0.

Now all indices have been marked.

It can be shown that it is not possible to mark all indices earlier than the 8th second.

Hence, the answer is 8.

Example 2:

Input: nums = [1,3], changeIndices = [1,1,1,2,1,1,1]

Output: 6

Explanation: In this example, we have 7 seconds. The following operations can be performed to mark all indices:

Second 1: Choose index 2 and decrement nums[2] by one. nums becomes [1,2].

Second 2: Choose index 2 and decrement nums[2] by one. nums becomes [1,1].

Second 3: Choose index 2 and decrement nums[2] by one. nums becomes [1,0].

Second 4: Mark the index changeIndices[4], which is marking index 2, since nums[2] is equal to 0.

Second 5: Choose index 1 and decrement nums[1] by one. nums becomes [0,0].

Second 6: Mark the index changeIndices[6], which is marking index 1, since nums[1] is equal to 0.

Now all indices have been marked.

It can be shown that it is not possible to mark all indices earlier than the 6th second.

Hence, the answer is 6.

Example 3:

Input: nums = [0,1], changeIndices = [2,2,2]

Output: -1

Explanation: In this example, it is impossible to mark all indices because index 1 isn’t in changeIndices. Hence, the answer is -1.

Constraints:

  • 1 <= n == nums.length <= 2000
  • 0 <= nums[i] <= 109
  • 1 <= m == changeIndices.length <= 2000
  • 1 <= changeIndices[i] <= n

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    int
    earliestSecondToMarkIndices(int[] nums, int[] changeIndices)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • earliestSecondToMarkIndices

      public int earliestSecondToMarkIndices(int[] nums, int[] changeIndices)