Class Solution
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- All Implemented Interfaces:
public final class Solution
72 - Edit Distance\.
Hard
Given two strings
word1
andword2
, return the minimum number of operations required to convertword1
toword2
.You have the following three operations permitted on a word:
Insert a character
Delete a character
Replace a character
Example 1:
Input: word1 = "horse", word2 = "ros"
Output: 3
Explanation:
horse -> rorse (replace 'h' with 'r')
rorse -> rose (remove 'r')
rose -> ros (remove 'e')
Example 2:
Input: word1 = "intention", word2 = "execution"
Output: 5
Explanation:
intention -> inention (remove 't')
inention -> enention (replace 'i' with 'e')
enention -> exention (replace 'n' with 'x')
exention -> exection (replace 'n' with 'c')
exection -> execution (insert 'u')
Constraints:
0 <= word1.length, word2.length <= 500
word1
andword2
consist of lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
minDistance(String word1, String word2)
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Method Detail
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minDistance
final Integer minDistance(String word1, String word2)
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