Class Solution
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public final class Solution
2012 - Sum of Beauty in the Array\.
Medium
You are given a 0-indexed integer array
nums
. For each indexi
(1 <= i <= nums.length - 2
) the beauty ofnums[i]
equals:2
, ifnums[j] < nums[i] < nums[k]
, for all0 <= j < i
and for alli < k <= nums.length - 1
.1
, ifnums[i - 1] < nums[i] < nums[i + 1]
, and the previous condition is not satisfied.0
, if none of the previous conditions holds.
Return the sum of beauty of all
nums[i]
where1 <= i <= nums.length - 2
.Example 1:
Input: nums = 1,2,3
Output: 2
Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums1 equals 2.
Example 2:
Input: nums = 2,4,6,4
Output: 1
Explanation: For each index i in the range 1 <= i <= 2:
The beauty of nums1 equals 1.
The beauty of nums2 equals 0.
Example 3:
Input: nums = 3,2,1
Output: 0
Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums1 equals 0.
Constraints:
<code>3 <= nums.length <= 10<sup>5</sup></code>
<code>1 <= numsi<= 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
sumOfBeauties(IntArray nums)
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Method Detail
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sumOfBeauties
final Integer sumOfBeauties(IntArray nums)
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