Class Solution

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    public final class Solution
    
                        

    892 - Surface Area of 3D Shapes\.

    Easy

    You are given an n x n grid where you have placed some 1 x 1 x 1 cubes. Each value v = grid[i][j] represents a tower of v cubes placed on top of cell (i, j).

    After placing these cubes, you have decided to glue any directly adjacent cubes to each other, forming several irregular 3D shapes.

    Return the total surface area of the resulting shapes.

    Note: The bottom face of each shape counts toward its surface area.

    Example 1:

    Input: grid = \[\[1,2],3,4]

    Output: 34

    Example 2:

    Input: grid = \[\[1,1,1],1,0,1,1,1,1]

    Output: 32

    Example 3:

    Input: grid = \[\[2,2,2],2,1,2,2,2,2]

    Output: 46

    Constraints:

    • n == grid.length == grid[i].length

    • 1 <= n <= 50

    • 0 <= grid[i][j] <= 50

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer surfaceArea(Array<IntArray> grid)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait