Class Solution
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public final class Solution
1808 - Maximize Number of Nice Divisors\.
Hard
You are given a positive integer
primeFactors
. You are asked to construct a positive integern
that satisfies the following conditions:The number of prime factors of
n
(not necessarily distinct) is at mostprimeFactors
.The number of nice divisors of
n
is maximized. Note that a divisor ofn
is nice if it is divisible by every prime factor ofn
. For example, ifn = 12
, then its prime factors are[2,2,3]
, then6
and12
are nice divisors, while3
and4
are not.
Return the number of nice divisors of
n
. Since that number can be too large, return it modulo <code>10<sup>9</sup> + 7</code>.Note that a prime number is a natural number greater than
1
that is not a product of two smaller natural numbers. The prime factors of a numbern
is a list of prime numbers such that their product equalsn
.Example 1:
Input: primeFactors = 5
Output: 6
Explanation: 200 is a valid value of n. It has 5 prime factors: 2,2,2,5,5, and it has 6 nice divisors: 10,20,40,50,100,200. There is not other value of n that has at most 5 prime factors and more nice divisors.
Example 2:
Input: primeFactors = 8
Output: 18
Constraints:
<code>1 <= primeFactors <= 10<sup>9</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
maxNiceDivisors(Integer pf)
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Method Detail
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maxNiceDivisors
final Integer maxNiceDivisors(Integer pf)
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