Class Solution
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public final class Solution
1862 - Sum of Floored Pairs\.
Hard
Given an integer array
nums
, return the sum offloor(nums[i] / nums[j])
for all pairs of indices0 <= i, j < nums.length
in the array. Since the answer may be too large, return it modulo <code>10<sup>9</sup> + 7</code>.The
floor()
function returns the integer part of the division.Example 1:
Input: nums = 2,5,9
Output: 10
Explanation:
floor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0
floor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1
floor(5 / 2) = 2
floor(9 / 2) = 4
floor(9 / 5) = 1
We calculate the floor of the division for every pair of indices in the array then sum them up.
Example 2:
Input: nums = 7,7,7,7,7,7,7
Output: 49
Constraints:
<code>1 <= nums.length <= 10<sup>5</sup></code>
<code>1 <= numsi<= 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
sumOfFlooredPairs(IntArray nums)
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Method Detail
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sumOfFlooredPairs
final Integer sumOfFlooredPairs(IntArray nums)
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