Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2012 - Sum of Beauty in the Array\.

    Medium

    You are given a 0-indexed integer array nums. For each index i (1 <= i <= nums.length - 2) the beauty of nums[i] equals:

    • 2, if nums[j] < nums[i] < nums[k], for all 0 <= j < i and for all i < k <= nums.length - 1.

    • 1, if nums[i - 1] < nums[i] < nums[i + 1], and the previous condition is not satisfied.

    • 0, if none of the previous conditions holds.

    Return the sum of beauty of all nums[i] where 1 <= i <= nums.length - 2.

    Example 1:

    Input: nums = 1,2,3

    Output: 2

    Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums1 equals 2.

    Example 2:

    Input: nums = 2,4,6,4

    Output: 1

    Explanation: For each index i in the range 1 <= i <= 2:

    • The beauty of nums1 equals 1.

    • The beauty of nums2 equals 0.

    Example 3:

    Input: nums = 3,2,1

    Output: 0

    Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums1 equals 0.

    Constraints:

    • <code>3 <= nums.length <= 10<sup>5</sup></code>

    • <code>1 <= numsi<= 10<sup>5</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer sumOfBeauties(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait