Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    433 - Minimum Genetic Mutation\.

    Medium

    A gene string can be represented by an 8-character long string, with choices from 'A', 'C', 'G', and 'T'.

    Suppose we need to investigate a mutation from a gene string startGene to a gene string endGene where one mutation is defined as one single character changed in the gene string.

    • For example, "AACCGGTT" --> "AACCGGTA" is one mutation.

    There is also a gene bank bank that records all the valid gene mutations. A gene must be in bank to make it a valid gene string.

    Given the two gene strings startGene and endGene and the gene bank bank, return the minimum number of mutations needed to mutate from startGene to endGene. If there is no such a mutation, return -1.

    Note that the starting point is assumed to be valid, so it might not be included in the bank.

    Example 1:

    Input: startGene = "AACCGGTT", endGene = "AACCGGTA", bank = "AACCGGTA"

    Output: 1

    Example 2:

    Input: startGene = "AACCGGTT", endGene = "AAACGGTA", bank = "AACCGGTA","AACCGCTA","AAACGGTA"

    Output: 2

    Constraints:

    • 0 <= bank.length <= 10

    • startGene.length == endGene.length == bank[i].length == 8

    • startGene, endGene, and bank[i] consist of only the characters ['A', 'C', 'G', 'T'].

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer minMutation(String start, String end, Array<String> bank)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait