Class Solution
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public final class Solution
936 - Stamping The Sequence\.
Hard
You are given two strings
stamp
andtarget
. Initially, there is a strings
of lengthtarget.length
with alls[i] == '?'
.In one turn, you can place
stamp
overs
and replace every letter in thes
with the corresponding letter fromstamp
.For example, if
stamp = "abc"
andtarget = "abcba"
, thens
is"?????"
initially. In one turn you can:place
stamp
at index0
ofs
to obtain"abc??"
,place
stamp
at index1
ofs
to obtain"?abc?"
, orplace
stamp
at index2
ofs
to obtain"??abc"
.
Note that
stamp
must be fully contained in the boundaries ofs
in order to stamp (i.e., you cannot placestamp
at index3
ofs
).
We want to convert
s
totarget
using at most10 * target.length
turns.Return an array of the index of the left-most letter being stamped at each turn. If we cannot obtain
target
froms
within10 * target.length
turns, return an empty array.Example 1:
Input: stamp = "abc", target = "ababc"
Output: 0,2
Explanation: Initially s = "?????".
Place stamp at index 0 to get "abc??".
Place stamp at index 2 to get "ababc".
1,0,2 would also be accepted as an answer, as well as some other answers.
Example 2:
Input: stamp = "abca", target = "aabcaca"
Output: 3,0,1
Explanation: Initially s = "???????".
Place stamp at index 3 to get "???abca".
Place stamp at index 0 to get "abcabca".
Place stamp at index 1 to get "aabcaca".
Constraints:
1 <= stamp.length <= target.length <= 1000
stamp
andtarget
consist of lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntArray
movesToStamp(String stamp, String target)
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Method Detail
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movesToStamp
final IntArray movesToStamp(String stamp, String target)
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