Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2000 - Reverse Prefix of Word\.

    Easy

    Given a 0-indexed string word and a character ch, reverse the segment of word that starts at index 0 and ends at the index of the first occurrence of ch ( inclusive ). If the character ch does not exist in word, do nothing.

    • For example, if word = "abcdefd" and ch = "d", then you should reverse the segment that starts at 0 and ends at 3 ( inclusive ). The resulting string will be "dcbaefd".

    Return the resulting string.

    Example 1:

    Input: word = "abcdefd", ch = "d"

    Output: "dcbaefd"

    Explanation: The first occurrence of "d" is at index 3.

    Reverse the part of word from 0 to 3 (inclusive), the resulting string is "dcbaefd".

    Example 2:

    Input: word = "xyxzxe", ch = "z"

    Output: "zxyxxe"

    Explanation: The first and only occurrence of "z" is at index 3.

    Reverse the part of word from 0 to 3 (inclusive), the resulting string is "zxyxxe".

    Example 3:

    Input: word = "abcd", ch = "z"

    Output: "abcd"

    Explanation: "z" does not exist in word.

    You should not do any reverse operation, the resulting string is "abcd".

    Constraints:

    • 1 <= word.length <= 250

    • word consists of lowercase English letters.

    • ch is a lowercase English letter.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final String reversePrefix(String word, Character ch)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait