Class Solution

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    public final class Solution
    
                        

    97 - Interleaving String\.

    Medium

    Given strings s1, s2, and s3, find whether s3 is formed by an interleaving of s1 and s2.

    An interleaving of two strings s and t is a configuration where s and t are divided into n and m non-empty substrings respectively, such that:

    • <code>s = s<sub>1</sub> + s<sub>2</sub> + ... + s<sub>n</sub></code>

    • <code>t = t<sub>1</sub> + t<sub>2</sub> + ... + t<sub>m</sub></code>

    • |n - m| &lt;= 1

    • The interleaving is <code>s<sub>1</sub> + t<sub>1</sub> + s<sub>2</sub> + t<sub>2</sub> + s<sub>3</sub> + t<sub>3</sub> + ...</code> or <code>t<sub>1</sub> + s<sub>1</sub> + t<sub>2</sub> + s<sub>2</sub> + t<sub>3</sub> + s<sub>3</sub> + ...</code>

    Note: a + b is the concatenation of strings a and b.

    Example 1:

    Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac"

    Output: true

    Explanation: One way to obtain s3 is: Split s1 into s1 = "aa" + "bc" + "c", and s2 into s2 = "dbbc" + "a". Interleaving the two splits, we get "aa" + "dbbc" + "bc" + "a" + "c" = "aadbbcbcac". Since s3 can be obtained by interleaving s1 and s2, we return true.

    Example 2:

    Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc"

    Output: false

    Explanation: Notice how it is impossible to interleave s2 with any other string to obtain s3.

    Example 3:

    Input: s1 = "", s2 = "", s3 = ""

    Output: true

    Constraints:

    • 0 &lt;= s1.length, s2.length &lt;= 100

    • 0 &lt;= s3.length &lt;= 200

    • s1, s2, and s3 consist of lowercase English letters.

    Follow up: Could you solve it using only O(s2.length) additional memory space?

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      Solution()
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