Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    140 - Word Break II\.

    Hard

    Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order.

    Note that the same word in the dictionary may be reused multiple times in the segmentation.

    Example 1:

    Input: s = "catsanddog", wordDict = "cat","cats","and","sand","dog"

    Output: "cats and dog","cat sand dog"

    Example 2:

    Input: s = "pineapplepenapple", wordDict = "apple","pen","applepen","pine","pineapple"

    Output: "pine apple pen apple","pineapple pen apple","pine applepen apple"

    Explanation: Note that you are allowed to reuse a dictionary word.

    Example 3:

    Input: s = "catsandog", wordDict = "cats","dog","sand","and","cat"

    Output: []

    Constraints:

    • 1 <= s.length <= 20

    • 1 <= wordDict.length <= 1000

    • 1 <= wordDict[i].length <= 10

    • s and wordDict[i] consist of only lowercase English letters.

    • All the strings of wordDict are unique.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final List<String> wordBreak(String s, List<String> wordDict)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait