Class Solution
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public final class Solution
315 - Count of Smaller Numbers After Self\.
Hard
You are given an integer array
nums
and you have to return a newcounts
array. Thecounts
array has the property wherecounts[i]
is the number of smaller elements to the right ofnums[i]
.Example 1:
Input: nums = 5,2,6,1
Output: 2,1,1,0
Explanation: To the right of 5 there are 2 smaller elements (2 and 1). To the right of 2 there is only 1 smaller element (1). To the right of 6 there is 1 smaller element (1). To the right of 1 there is 0 smaller element.
Example 2:
Input: nums = -1
Output: 0
Example 3:
Input: nums = -1,-1
Output: 0,0
Constraints:
<code>1 <= nums.length <= 10<sup>5</sup></code>
<code>-10<sup>4</sup><= numsi<= 10<sup>4</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final List<Integer>
countSmaller(IntArray nums)
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Method Detail
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countSmaller
final List<Integer> countSmaller(IntArray nums)
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