Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    328 - Odd Even Linked List\.

    Medium

    Given the head of a singly linked list, group all the nodes with odd indices together followed by the nodes with even indices, and return the reordered list.

    The first node is considered odd , and the second node is even , and so on.

    Note that the relative order inside both the even and odd groups should remain as it was in the input.

    You must solve the problem in O(1) extra space complexity and O(n) time complexity.

    Example 1:

    Input: head = 1,2,3,4,5

    Output: 1,3,5,2,4

    Example 2:

    Input: head = 2,1,3,5,6,4,7

    Output: 2,3,6,7,1,5,4

    Constraints:

    • The number of nodes in the linked list is in the range <code>0, 10<sup>4</sup></code>.

    • <code>-10<sup>6</sup><= Node.val <= 10<sup>6</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final ListNode oddEvenList(ListNode head)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait