Class Solution
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public final class Solution
328 - Odd Even Linked List\.
Medium
Given the
head
of a singly linked list, group all the nodes with odd indices together followed by the nodes with even indices, and return the reordered list.The first node is considered odd , and the second node is even , and so on.
Note that the relative order inside both the even and odd groups should remain as it was in the input.
You must solve the problem in
O(1)
extra space complexity andO(n)
time complexity.Example 1:
Input: head = 1,2,3,4,5
Output: 1,3,5,2,4
Example 2:
Input: head = 2,1,3,5,6,4,7
Output: 2,3,6,7,1,5,4
Constraints:
The number of nodes in the linked list is in the range <code>0, 10<sup>4</sup></code>.
<code>-10<sup>6</sup><= Node.val <= 10<sup>6</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final ListNode
oddEvenList(ListNode head)
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Method Detail
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oddEvenList
final ListNode oddEvenList(ListNode head)
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