Class Solution
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public final class Solution
674 - Longest Continuous Increasing Subsequence\.
Easy
Given an unsorted array of integers
nums
, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing.A continuous increasing subsequence is defined by two indices
l
andr
(l < r
) such that it is[nums[l], nums[l + 1], ..., nums[r - 1], nums[r]]
and for eachl <= i < r
,nums[i] < nums[i + 1]
.Example 1:
Input: nums = 1,3,5,4,7
Output: 3
Explanation: The longest continuous increasing subsequence is 1,3,5 with length 3. Even though 1,3,5,7 is an increasing subsequence, it is not continuous as elements 5 and 7 are separated by element 4.
Example 2:
Input: nums = 2,2,2,2,2
Output: 1
Explanation: The longest continuous increasing subsequence is 2 with length 1. Note that it must be strictly increasing.
Constraints:
<code>1 <= nums.length <= 10<sup>4</sup></code>
<code>-10<sup>9</sup><= numsi<= 10<sup>9</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
findLengthOfLCIS(IntArray nums)
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Method Detail
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findLengthOfLCIS
final Integer findLengthOfLCIS(IntArray nums)
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