Class Solution

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    public final class Solution
    
                        

    674 - Longest Continuous Increasing Subsequence\.

    Easy

    Given an unsorted array of integers nums, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing.

    A continuous increasing subsequence is defined by two indices l and r (l < r) such that it is [nums[l], nums[l + 1], ..., nums[r - 1], nums[r]] and for each l <= i < r, nums[i] < nums[i + 1].

    Example 1:

    Input: nums = 1,3,5,4,7

    Output: 3

    Explanation: The longest continuous increasing subsequence is 1,3,5 with length 3. Even though 1,3,5,7 is an increasing subsequence, it is not continuous as elements 5 and 7 are separated by element 4.

    Example 2:

    Input: nums = 2,2,2,2,2

    Output: 1

    Explanation: The longest continuous increasing subsequence is 2 with length 1. Note that it must be strictly increasing.

    Constraints:

    • <code>1 <= nums.length <= 10<sup>4</sup></code>

    • <code>-10<sup>9</sup><= numsi<= 10<sup>9</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer findLengthOfLCIS(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait