Class Solution
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public final class Solution
730 - Count Different Palindromic Subsequences\.
Hard
Given a string s, return the number of different non-empty palindromic subsequences in
s
. Since the answer may be very large, return it modulo <code>10<sup>9</sup> + 7</code>.A subsequence of a string is obtained by deleting zero or more characters from the string.
A sequence is palindromic if it is equal to the sequence reversed.
Two sequences <code>a<sub>1</sub>, a<sub>2</sub>, ...</code> and <code>b<sub>1</sub>, b<sub>2</sub>, ...</code> are different if there is some
i
for which <code>a<sub>i</sub> != b<sub>i</sub></code>.Example 1:
Input: s = "bccb"
Output: 6
Explanation: The 6 different non-empty palindromic subsequences are 'b', 'c', 'bb', 'cc', 'bcb', 'bccb'. Note that 'bcb' is counted only once, even though it occurs twice.
Example 2:
Input: s = "abcdabcdabcdabcdabcdabcdabcdabcddcbadcbadcbadcbadcbadcbadcbadcba"
Output: 104860361
Explanation: There are 3104860382 different non-empty palindromic subsequences, which is 104860361 modulo 10<sup>9</sup> + 7.
Constraints:
1 <= s.length <= 1000
s[i]
is either'a'
,'b'
,'c'
, or'd'
.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
countPalindromicSubsequences(String s)
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Method Detail
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countPalindromicSubsequences
final Integer countPalindromicSubsequences(String s)
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