Class Solution

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    public final class Solution
    
                        

    835 - Image Overlap\.

    Medium

    You are given two images, img1 and img2, represented as binary, square matrices of size n x n. A binary matrix has only 0s and 1s as values.

    We translate one image however we choose by sliding all the 1 bits left, right, up, and/or down any number of units. We then place it on top of the other image. We can then calculate the overlap by counting the number of positions that have a 1 in both images.

    Note also that a translation does not include any kind of rotation. Any 1 bits that are translated outside of the matrix borders are erased.

    Return the largest possible overlap.

    Example 1:

    Input: img1 = \[\[1,1,0],0,1,0,0,1,0], img2 = \[\[0,0,0],0,1,1,0,0,1]

    Output: 3

    Explanation: We translate img1 to right by 1 unit and down by 1 unit. The number of positions that have a 1 in both images is 3 (shown in red).

    Example 2:

    Input: img1 = \[\[1]], img2 = \[\[1]]

    Output: 1

    Example 3:

    Input: img1 = \[\[0]], img2 = \[\[0]]

    Output: 0

    Constraints:

    • n == img1.length == img1[i].length

    • n == img2.length == img2[i].length

    • 1 <= n <= 30

    • img1[i][j] is either 0 or 1.

    • img2[i][j] is either 0 or 1.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer largestOverlap(Array<IntArray> img1, Array<IntArray> img2)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait