Package g0801_0900.s0844_backspace_string_compare

Class Solution

  • All Implemented Interfaces:
    
public final class Solution

    844 - Backspace String Compare\.

    Easy

    Given two strings s and t, return true if they are equal when both are typed into empty text editors. '#' means a backspace character.

    Note that after backspacing an empty text, the text will continue empty.

    Example 1:

    Input: s = "ab#c", t = "ad#c"

    Output: true

    Explanation: Both s and t become "ac".

    Example 2:

    Input: s = "ab##", t = "c#d#"

    Output: true

    Explanation: Both s and t become "".

    Example 3:

    Input: s = "a#c", t = "b"

    Output: false

    Explanation: s becomes "c" while t becomes "b".

    Constraints:

    • 1 <= s.length, t.length <= 200

    • s and t only contain lowercase letters and '#' characters.

    Follow up: Can you solve it in O(n) time and O(1) space?

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description

    • Field Summary

      Fields 
      Modifier and Type Field Description

    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()

    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description

    • Method Summary

      Modifier and Type Method Description
      final Boolean backspaceCompare(String s, String t)

      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait