Class Solution
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- All Implemented Interfaces:
public final class Solution
880 - Decoded String at Index\.
Medium
You are given an encoded string
s
. To decode the string to a tape, the encoded string is read one character at a time and the following steps are taken:If the character read is a letter, that letter is written onto the tape.
If the character read is a digit
d
, the entire current tape is repeatedly writtend - 1
more times in total.
Given an integer
k
, return the <code>k<sup>th</sup></code> letter ( 1-indexed) in the decoded string.Example 1:
Input: s = "leet2code3", k = 10
Output: "o"
Explanation: The decoded string is "leetleetcodeleetleetcodeleetleetcode". The 10<sup>th</sup> letter in the string is "o".
Example 2:
Input: s = "ha22", k = 5
Output: "h"
Explanation: The decoded string is "hahahaha". The 5<sup>th</sup> letter is "h".
Example 3:
Input: s = "a2345678999999999999999", k = 1
Output: "a"
Explanation: The decoded string is "a" repeated 8301530446056247680 times. The 1<sup>st</sup> letter is "a".
Constraints:
2 <= s.length <= 100
s
consists of lowercase English letters and digits2
through9
.s
starts with a letter.<code>1 <= k <= 10<sup>9</sup></code>
It is guaranteed that
k
is less than or equal to the length of the decoded string.The decoded string is guaranteed to have less than <code>2<sup>63</sup></code> letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final String
decodeAtIndex(String s, Integer k)
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Method Detail
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decodeAtIndex
final String decodeAtIndex(String s, Integer k)
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