Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    975 - Odd Even Jump\.

    Hard

    You are given an integer array arr. From some starting index, you can make a series of jumps. The (1<sup>st</sup>, 3<sup>rd</sup>, 5<sup>th</sup>, ...) jumps in the series are called odd-numbered jumps , and the (2<sup>nd</sup>, 4<sup>th</sup>, 6<sup>th</sup>, ...) jumps in the series are called even-numbered jumps. Note that the jumps are numbered, not the indices.

    You may jump forward from index i to index j (with i &lt; j) in the following way:

    • During odd-numbered jumps (i.e., jumps 1, 3, 5, ...), you jump to the index j such that arr[i] &lt;= arr[j] and arr[j] is the smallest possible value. If there are multiple such indices j, you can only jump to the smallest such index j.

    • During even-numbered jumps (i.e., jumps 2, 4, 6, ...), you jump to the index j such that arr[i] &gt;= arr[j] and arr[j] is the largest possible value. If there are multiple such indices j, you can only jump to the smallest such index j.

    • It may be the case that for some index i, there are no legal jumps.

    A starting index is good if, starting from that index, you can reach the end of the array (index arr.length - 1) by jumping some number of times (possibly 0 or more than once).

    Return the number of good starting indices.

    Example 1:

    Input: arr = 10,13,12,14,15

    Output: 2

    Explanation:

    From starting index i = 0, we can make our 1st jump to i = 2 (since arr2 is the smallest among arr1,

    arr2, arr3, arr4 that is greater or equal to arr0), then we cannot jump any more.

    From starting index i = 1 and i = 2, we can make our 1st jump to i = 3, then we cannot jump any more.

    From starting index i = 3, we can make our 1st jump to i = 4, so we have reached the end.

    From starting index i = 4, we have reached the end already.

    In total, there are 2 different starting indices i = 3 and i = 4, where we can reach the end with some number of jumps.

    Example 2:

    Input: arr = 2,3,1,1,4

    Output: 3

    Explanation:

    From starting index i = 0, we make jumps to i = 1, i = 2, i = 3:

    During our 1st jump (odd-numbered), we first jump to i = 1 because arr1 is the smallest value in [arr1,

    arr2, arr3, arr4] that is greater than or equal to arr0.

    During our 2nd jump (even-numbered), we jump from i = 1 to i = 2 because arr2 is the largest value in

    [arr2, arr3, arr4] that is less than or equal to arr1. arr3 is also the largest value, but 2 is a

    smaller index, so we can only jump to i = 2 and not i = 3

    During our 3rd jump (odd-numbered), we jump from i = 2 to i = 3 because arr3 is the smallest value in

    [arr3, arr4] that is greater than or equal to arr2.

    We can't jump from i = 3 to i = 4, so the starting index i = 0 is not good.

    In a similar manner, we can deduce that: From starting index i = 1, we jump to i = 4, so we reach the end.

    From starting index i = 2, we jump to i = 3, and then we can't jump anymore.

    From starting index i = 3, we jump to i = 4, so we reach the end.

    From starting index i = 4, we are already at the end.

    In total, there are 3 different starting indices i = 1, i = 3, and i = 4, where we can reach the end with

    some number of jumps.

    Example 3:

    Input: arr = 5,1,3,4,2

    Output: 3

    Explanation: We can reach the end from starting indices 1, 2, and 4.

    Constraints:

    • <code>1 <= arr.length <= 2 * 10<sup>4</sup></code>

    • <code>0 <= arri< 10<sup>5</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer oddEvenJumps(IntArray arr)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait