Class Solution
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public final class Solution
1015 - Smallest Integer Divisible by K\.
Medium
Given a positive integer
k
, you need to find the length of the smallest positive integern
such thatn
is divisible byk
, andn
only contains the digit1
.Return the length of
n
. If there is no suchn
, return -1.Note:
n
may not fit in a 64-bit signed integer.Example 1:
Input: k = 1
Output: 1
Explanation: The smallest answer is n = 1, which has length 1.
Example 2:
Input: k = 2
Output: -1
Explanation: There is no such positive integer n divisible by 2.
Example 3:
Input: k = 3
Output: 3
Explanation: The smallest answer is n = 111, which has length 3.
Constraints:
<code>1 <= k <= 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
smallestRepunitDivByK(Integer k)
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Method Detail
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smallestRepunitDivByK
final Integer smallestRepunitDivByK(Integer k)
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