Class Solution
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public final class Solution
1071 - Greatest Common Divisor of Strings\.
Easy
For two strings
s
andt
, we say "t
dividess
" if and only ifs = t + ... + t
(i.e.,t
is concatenated with itself one or more times).Given two strings
str1
andstr2
, return the largest stringx
such thatx
divides bothstr1
andstr2
.Example 1:
Input: str1 = "ABCABC", str2 = "ABC"
Output: "ABC"
Example 2:
Input: str1 = "ABABAB", str2 = "ABAB"
Output: "AB"
Example 3:
Input: str1 = "LEET", str2 = "CODE"
Output: ""
Constraints:
1 <= str1.length, str2.length <= 1000
str1
andstr2
consist of English uppercase letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final String
gcdOfStrings(String str1, String str2)
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Method Detail
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gcdOfStrings
final String gcdOfStrings(String str1, String str2)
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