Package g1401_1500.s1480_running_sum_of_1d_array

Class Solution

  • All Implemented Interfaces:
    
public final class Solution

    1480 - Running Sum of 1d Array\.

    Easy

    Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

    Return the running sum of nums.

    Example 1:

    Input: nums = 1,2,3,4

    Output: 1,3,6,10

    Explanation: Running sum is obtained as follows: 1, 1+2, 1+2+3, 1+2+3+4.

    Example 2:

    Input: nums = 1,1,1,1,1

    Output: 1,2,3,4,5

    Explanation: Running sum is obtained as follows: 1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1.

    Example 3:

    Input: nums = 3,1,2,10,1

    Output: 3,4,6,16,17

    Constraints:

    • 1 <= nums.length <= 1000

    • -10^6 <= nums[i] <= 10^6

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description

    • Field Summary

      Fields 
      Modifier and Type Field Description

    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()

    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description

    • Method Summary

      Modifier and Type Method Description
      final IntArray runningSum(IntArray nums)

      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait