Class Solution

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    public final class Solution
    
                        

    1582 - Special Positions in a Binary Matrix\.

    Easy

    Given an m x n binary matrix mat, return the number of special positions in mat.

    A position (i, j) is called special if mat[i][j] == 1 and all other elements in row i and column j are 0 (rows and columns are 0-indexed ).

    Example 1:

    Input: mat = \[\[1,0,0],0,0,1,1,0,0]

    Output: 1

    Explanation: (1, 2) is a special position because mat2 == 1 and all other elements in row 1 and column 2 are 0.

    Example 2:

    Input: mat = \[\[1,0,0],0,1,0,0,0,1]

    Output: 3

    Explanation: (0, 0), (1, 1) and (2, 2) are special positions.

    Constraints:

    • m == mat.length

    • n == mat[i].length

    • 1 <= m, n <= 100

    • mat[i][j] is either 0 or 1.

    • Nested Class Summary

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      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer numSpecial(Array<IntArray> mat)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait