Class Solution
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public final class Solution
1592 - Rearrange Spaces Between Words\.
Easy
You are given a string
text
of words that are placed among some number of spaces. Each word consists of one or more lowercase English letters and are separated by at least one space. It's guaranteed thattext
contains at least one word.Rearrange the spaces so that there is an equal number of spaces between every pair of adjacent words and that number is maximized. If you cannot redistribute all the spaces equally, place the extra spaces at the end , meaning the returned string should be the same length as
text
.Return the string after rearranging the spaces.
Example 1:
Input: text = " this is a sentence "
Output: "this is a sentence"
Explanation: There are a total of 9 spaces and 4 words. We can evenly divide the 9 spaces between the words: 9 / (4-1) = 3 spaces.
Example 2:
Input: text = " practice makes perfect"
Output: "practice makes perfect "
Explanation: There are a total of 7 spaces and 3 words. 7 / (3-1) = 3 spaces plus 1 extra space. We place this extra space at the end of the string.
Constraints:
1 <= text.length <= 100
text
consists of lowercase English letters and' '
.text
contains at least one word.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final String
reorderSpaces(String text)
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Method Detail
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reorderSpaces
final String reorderSpaces(String text)
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