Class Solution
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- All Implemented Interfaces:
public final class Solution
1971 - Find if Path Exists in Graph\.
Easy
There is a bi-directional graph with
n
vertices, where each vertex is labeled from0
ton - 1
( inclusive ). The edges in the graph are represented as a 2D integer arrayedges
, where each <code>edgesi = u<sub>i</sub>, v<sub>i</sub></code> denotes a bi-directional edge between vertex <code>u<sub>i</sub></code> and vertex <code>v<sub>i</sub></code>. Every vertex pair is connected by at most one edge, and no vertex has an edge to itself.You want to determine if there is a valid path that exists from vertex
source
to vertexdestination
.Given
edges
and the integersn
,source
, anddestination
, returntrue
if there is a valid path fromsource
todestination
, orfalse
otherwise_._Example 1:
Input: n = 3, edges = \[\[0,1],1,2,2,0], source = 0, destination = 2
Output: true
Explanation: There are two paths from vertex 0 to vertex 2: - 0 → 1 → 2 - 0 → 2
Example 2:
Input: n = 6, edges = \[\[0,1],0,2,3,5,5,4,4,3], source = 0, destination = 5
Output: false
Explanation: There is no path from vertex 0 to vertex 5.
Constraints:
<code>1 <= n <= 2 * 10<sup>5</sup></code>
<code>0 <= edges.length <= 2 * 10<sup>5</sup></code>
edges[i].length == 2
<code>0 <= u<sub>i</sub>, v<sub>i</sub><= n - 1</code>
<code>u<sub>i</sub> != v<sub>i</sub></code>
0 <= source, destination <= n - 1
There are no duplicate edges.
There are no self edges.
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Constructor Summary
Constructors Constructor Description Solution()
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