2094 - Finding 3-Digit Even Numbers\.

Easy

You are given an integer array digits, where each element is a digit. The array may contain duplicates.

You need to find all the unique integers that follow the given requirements:

• The integer consists of the concatenation of three elements from digits in any arbitrary order.

• The integer does not have leading zeros.

• The integer is even.

For example, if the given digits were [1, 2, 3], integers 132 and 312 follow the requirements.

Return a sorted array of the unique integers.

Example 1:

Input: digits = 2,1,3,0

Output: 102,120,130,132,210,230,302,310,312,320

Explanation: All the possible integers that follow the requirements are in the output array.

Notice that there are no odd integers or integers with leading zeros.

Example 2:

Input: digits = 2,2,8,8,2

Output: 222,228,282,288,822,828,882

Explanation: The same digit can be used as many times as it appears in digits.

In this example, the digit 8 is used twice each time in 288, 828, and 882.

Example 3:

Input: digits = 3,7,5

Output: []

Explanation: No even integers can be formed using the given digits.

Constraints:

• 3 <= digits.length <= 100

• 0 <= digits[i] <= 9