Class Solution

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    public final class Solution
    
                        

    2226 - Maximum Candies Allocated to K Children\.

    Medium

    You are given a 0-indexed integer array candies. Each element in the array denotes a pile of candies of size candies[i]. You can divide each pile into any number of sub piles , but you cannot merge two piles together.

    You are also given an integer k. You should allocate piles of candies to k children such that each child gets the same number of candies. Each child can take at most one pile of candies and some piles of candies may go unused.

    Return the maximum number of candies each child can get.

    Example 1:

    Input: candies = 5,8,6, k = 3

    Output: 5

    Explanation: We can divide candies1 into 2 piles of size 5 and 3, and candies2 into 2 piles of size 5 and 1. We now have five piles of candies of sizes 5, 5, 3, 5, and 1. We can allocate the 3 piles of size 5 to 3 children. It can be proven that each child cannot receive more than 5 candies.

    Example 2:

    Input: candies = 2,5, k = 11

    Output: 0

    Explanation: There are 11 children but only 7 candies in total, so it is impossible to ensure each child receives at least one candy. Thus, each child gets no candy and the answer is 0.

    Constraints:

    • <code>1 <= candies.length <= 10<sup>5</sup></code>

    • <code>1 <= candiesi<= 10<sup>7</sup></code>

    • <code>1 <= k <= 10<sup>12</sup></code>

    • Nested Class Summary

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      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer maximumCandies(IntArray candies, Long k)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait