Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2864 - Maximum Odd Binary Number\.

    Easy

    You are given a binary string s that contains at least one '1'.

    You have to rearrange the bits in such a way that the resulting binary number is the maximum odd binary number that can be created from this combination.

    Return a string representing the maximum odd binary number that can be created from the given combination.

    Note that the resulting string can have leading zeros.

    Example 1:

    Input: s = "010"

    Output: "001"

    Explanation: Because there is just one '1', it must be in the last position. So the answer is "001".

    Example 2:

    Input: s = "0101"

    Output: "1001"

    Explanation: One of the '1's must be in the last position. The maximum number that can be made with the remaining digits is "100". So the answer is "1001".

    Constraints:

    • 1 <= s.length <= 100

    • s consists only of '0' and '1'.

    • s contains at least one '1'.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final String maximumOddBinaryNumber(String s)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait