Class Solution
-
- All Implemented Interfaces:
public final class Solution
2924 - Find Champion II\.
Medium
There are
n
teams numbered from0
ton - 1
in a tournament; each team is also a node in a DAG.You are given the integer
n
and a 0-indexed 2D integer arrayedges
of lengthm
representing the DAG , where <code>edgesi = u<sub>i</sub>, v<sub>i</sub></code> indicates that there is a directed edge from team <code>u<sub>i</sub></code> to team <code>v<sub>i</sub></code> in the graph.A directed edge from
a
tob
in the graph means that teama
is stronger than teamb
and teamb
is weaker than teama
.Team
a
will be the champion of the tournament if there is no teamb
that is stronger than teama
.Return the team that will be the champion of the tournament if there is a unique champion, otherwise, return
-1
.Notes
A cycle is a series of nodes <code>a<sub>1</sub>, a<sub>2</sub>, ..., a<sub>n</sub>, a<sub>n+1</sub></code> such that node <code>a<sub>1</sub></code> is the same node as node <code>a<sub>n+1</sub></code>, the nodes <code>a<sub>1</sub>, a<sub>2</sub>, ..., a<sub>n</sub></code> are distinct, and there is a directed edge from the node <code>a<sub>i</sub></code> to node <code>a<sub>i+1</sub></code> for every
i
in the range[1, n]
.A DAG is a directed graph that does not have any cycle.
Example 1:
Input: n = 3, edges = \[\[0,1],1,2]
Output: 0
Explanation: Team 1 is weaker than team 0. Team 2 is weaker than team 1. So the champion is team 0.
Example 2:
Input: n = 4, edges = \[\[0,2],1,3,1,2]
Output: -1
Explanation: Team 2 is weaker than team 0 and team 1. Team 3 is weaker than team 1. But team 1 and team 0 are not weaker than any other teams. So the answer is -1.
Constraints:
1 <= n <= 100
m == edges.length
0 <= m <= n * (n - 1) / 2
edges[i].length == 2
0 <= edge[i][j] <= n - 1
edges[i][0] != edges[i][1]
The input is generated such that if team
a
is stronger than teamb
, teamb
is not stronger than teama
.The input is generated such that if team
a
is stronger than teamb
and teamb
is stronger than teamc
, then teama
is stronger than teamc
.