Class Solution
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public final class Solution
3045 - Count Prefix and Suffix Pairs II\.
Hard
You are given a 0-indexed string array
words
.Let's define a boolean function
isPrefixAndSuffix
that takes two strings,str1
andstr2
:isPrefixAndSuffix(str1, str2)
returnstrue
ifstr1
is both a prefix and a suffix ofstr2
, andfalse
otherwise.
For example,
isPrefixAndSuffix("aba", "ababa")
istrue
because"aba"
is a prefix of"ababa"
and also a suffix, butisPrefixAndSuffix("abc", "abcd")
isfalse
.Return an integer denoting the number of index pairs
(i_,_ j)
such thati < j
, andisPrefixAndSuffix(words[i], words[j])
istrue
.Example 1:
Input: words = "a","aba","ababa","aa"
Output: 4
Explanation: In this example, the counted index pairs are:
i = 0 and j = 1 because isPrefixAndSuffix("a", "aba") is true.
i = 0 and j = 2 because isPrefixAndSuffix("a", "ababa") is true.
i = 0 and j = 3 because isPrefixAndSuffix("a", "aa") is true.
i = 1 and j = 2 because isPrefixAndSuffix("aba", "ababa") is true.
Therefore, the answer is 4.
Example 2:
Input: words = "pa","papa","ma","mama"
Output: 2
Explanation: In this example, the counted index pairs are:
i = 0 and j = 1 because isPrefixAndSuffix("pa", "papa") is true.
i = 2 and j = 3 because isPrefixAndSuffix("ma", "mama") is true.
Therefore, the answer is 2.
Example 3:
Input: words = "abab","ab"
Output: 0
Explanation: In this example, the only valid index pair is i = 0 and j = 1, and isPrefixAndSuffix("abab", "ab") is false.
Therefore, the answer is 0.
Constraints:
<code>1 <= words.length <= 10<sup>5</sup></code>
<code>1 <= wordsi.length <= 10<sup>5</sup></code>
words[i]
consists only of lowercase English letters.The sum of the lengths of all
words[i]
does not exceed <code>5 * 10<sup>5</sup></code>.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Long
countPrefixSuffixPairs(Array<String> words)
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Method Detail
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countPrefixSuffixPairs
final Long countPrefixSuffixPairs(Array<String> words)
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